Some example magnetic moment data and their
interpretation
Summary of applicable formulae
1) Spin-Only magnetic moment
μs.o. = √{4S(S+1)} B.M.
2) For A and E ground terms
μeff = μs.o. (1-α λ /Δ) B.M.
Do not expect Temperature dependence.
3) For T ground terms with orbital angular momentum contribution
μS+L = √{4S(S+1) + L(L+1)} B.M.
T terms generally show marked Temperature dependence.
The examples that follow are arranged showing the experimentally
observed values, the theoretical "spin-only" value and possible
variations expected.
A number of the examples involve "alums" where the central Transition
Metal ion can be considered to be octahedrally coordinated by water molecules.
d1
VCl4
V(IV) tetrahedral
80K 300K μs.o. /B.M.
1.6 1.6 1.73
2E ground term - hence don't expect Temperature
dependence and small variation from spin-only value can be accounted
for by equation 2) above. For less than a half-filled d shell, the sign of
λ is positive so the effect on μ should be that
μeff < μs.o.
VCl62-
V(IV) octahedral
80K 300K μs.o. /B.M.
1.4 1.8 1.73
2T2g ground term - hence do expect Temperature
dependence and large variation from spin-only value may be observed at
low temperatures.
Since there is a direct orbital angular momentum contribution we should
calculate μS+L from equation 3) above.
For a full S+L contribution this would give μS+L = 3 B.M.
which is clearly much higher than the 1.8 B.M. found at 300K.
So, μs.o. < μobs < μS+L
showing that the magnetic moment is partially quenched.
d2
V3+ in (NH4)V(SO4)2.12H2O (an alum)
V(III) octahedral
80K 300K μs.o. /B.M.
2.7 2.7 2.83
3T1g ground term - hence do expect Temperature
dependence and large variation from spin-only value may be observed at
low temperatures.
Since there is a direct orbital angular momentum contribution we should
calculate μS+L from equation 3) above.
For a full S+L contribution this would give μS+L = √(20) = 4.47 B.M.
which is clearly much higher than the 2.7 B.M. found at 300K.
So, μobs < μs.o. < μS+L
showing that the magnetic moment is significantly quenched.
In this case, there is no observed Temperature variation between 80 and 300K and
it may require much lower temperatures to see the effect?
d3
Cr3+ in KCr(SO4)2.12H2O (an alum)
Cr(III) octahedral
80K 300K μs.o. /B.M.
3.8 3.8 3.87
4A2g ground term - hence don't expect Temperature
dependence and small variation from spin-only value can be accounted
for by equation 2) above. For less than a half-filled d shell the sign of
λ is positive so the effect on μ should be that
μeff < μs.o.
d4
CrSO4.6H2O
Cr(II) octahedral
80K 300K μs.o. /B.M.
4.8 4.8 4.9
5Eg ground term - hence don't expect Temperature
dependence and small variation from spin-only value can be accounted
for by equation 2) above. For less than a half-filled d shell the sign of
λ is positive so the effect on μ should be that
μeff < μs.o.
K3Mn(CN)6
Mn(III) low-spin octahedral
80K 300K μs.o. /B.M.
3.1 3.2 2.83
3T1g ground term - hence do expect Temperature
dependence and large variation from spin-only value may be observed at
low temperatures.
Since there is a direct orbital angular momentum contribution we should
calculate μS+L from equation 3) above.
For a full S+L contribution this would give μS+L = √(20) = 4.47 B.M.
which is clearly much higher than the 3.2 B.M. found at 300K.
So, μs.o. < μobs < μS+L
showing that the magnetic moment is partially quenched.
In this case, there is a small Temperature variation observed between 80 and 300K.
d5
K2Mn(SO4)2.6H2O (an alum)
Mn(II) high-spin octahedral
80K 300K μs.o. /B.M.
5.9 5.9 5.92
6A1g ground term - hence do not expect Temperature
dependence and L=0 so no orbital contribution possible.
Expect μeff = μs.o.
K3Fe(CN)6
Fe(III) low-spin octahedral
80K 300K μs.o. /B.M.
2.2 2.4 1.73
2T2g ground term - hence do expect Temperature
dependence and large variation from spin-only value may be observed at
low temperatures.
Since there is a direct orbital angular momentum contribution we should
calculate μS+L from equation 3) above.
For a full S+L contribution this would give μS+L = √(9) = 3 B.M.
which is clearly much higher than the 2.4 B.M. found at 300K.
So, μs.o. < μobs < μS+L
showing that the magnetic moment is partially quenched.
d6
Fe2+ in (NH4)2Fe(SO4)2.6H2O (an alum)
Fe(II) high-spin octahedral
80K 300K μs.o. /B.M.
5.4 5.5 4.9
5T2g ground term - hence do expect Temperature
dependence and large variation from spin-only value may be observed at
low temperatures.
Since there is a direct orbital angular momentum contribution we should
calculate μS+L from equation 3) above.
For a full S+L contribution this would give μS+L = √(30) = 5.48 B.M.
which is close to the 5.5 B.M. found at 300K.
So, μs.o. < μobs ~ μS+L
showing that the magnetic moment is not showing much quenching.
d7
Cs2CoCl4
Co(II) tetrahedral
80K 300K μs.o. /B.M.
4.5 4.6 3.87
4A2 ground term - hence don't expect Temperature
dependence and small variation from spin-only value can be accounted
for by equation 2) above. For more than a half-filled d shell the sign of
λ is negative so the effect on μ should be that
μeff > μs.o.
The observed values are somewhat bigger than expected for the small (0.2 B.M.)
variation due to equation 2) so other factors must be affecting the magnetic moment.
These effects will not be covered in this course!
Co2+ in (NH4)2Co(SO4)2.6H2O (an alum)
Co(II) high-spin octahedral
80K 300K μs.o. /B.M.
4.6 5.1 3.88
4T1g ground term - hence do expect Temperature
dependence and large variation from spin-only value may be observed at
low temperatures.
Since there is a direct orbital angular momentum contribution we should
calculate μS+L from equation 3) above.
For a full S+L contribution this would give μS+L = √(27) = 5.2 B.M.
which is close to the 5.1 B.M. found at 300K.
So, μs.o. < μobs ~ μS+L
showing that the magnetic moment is not showing much quenching.
d8
Ni2+ in (NH4)2Ni(SO4)2.6H2O (an alum)
Ni(II) octahedral
80K 300K μs.o. /B.M.
3.3 3.3 2.83
3A2g ground term - hence don't expect Temperature
dependence and small variation from spin-only value can be accounted
for by equation 2) above. For more than a half-filled d shell the sign of
λ is negative so the effect on μ should be that
μeff > μs.o.
The observed values are somewhat bigger than expected for the small (0.2 B.M.)
variation due to equation 2) so other factors must be affecting the magnetic moment.
These effects will not be covered in this course!
(Et4N)2NiCl4
Ni(II) tetrahedral
80K 300K μs.o. /B.M.
3.2 3.8 2.83
3T2 ground term - hence do expect Temperature
dependence and large variation from spin-only value may be observed at
low temperatures.
Since there is a direct orbital angular momentum contribution we should
calculate μS+L from equation 3) above.
For a full S+L contribution this would give μS+L = √(20) = 4.47 B.M.
which is higher than the 3.8 B.M. found at 300K.
So, μs.o. < μobs < μS+L
showing that the magnetic moment is partially quenched.
d9
Cu2+ in (NH4)2Cu(SO4)2.6H2O (an alum)
Cu(II) octahedral
80K 300K μs.o. /B.M.
1.9 1.9 1.73
2Eg ground term - hence don't expect Temperature
dependence and small variation from spin-only value can be accounted
for by equation 2) above. For more than a half-filled d shell the sign of
λ is negative so the effect on μ should be that
μeff > μs.o.
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Lancashire,
The Department of Chemistry, University of the West Indies,
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Created October 2005. Links checked and/or last
modified 10th October 2010.
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